按题意直接模拟即可。

AC code：

#include <bits/stdc++.h>
using namespace std;

int main() {
	long long x1, x2, y1, y2;//不开long long见祖宗
	cin >> x1 >> y1 >> x2 >> y2;
	if (x1 != x2 && y1 != y2) {
        cout << x1 << " " << y2 << endl;
    } else if (x1 == x2 && y1 != y2) {
        cout << "0" << " " << y2 << endl;
    } else {
        cout << x1 << " " << "0" << endl;
    }
	return 0;
}

构造一条边平行于 $x$ 轴，一条边平行于 $y$ 轴的三角形即可。

#include <bits/stdc++.h>
#define y1 Y1
using namespace std;
int main()
{
	long long x1, x2, y1, y2;
	cin >> x1 >> y1 >> x2 >> y2;
	if (y1 != y2 && x1 != x2) cout << x1 << ' ' << y2 << endl;
	if (y1 == y2 && x1 != x2) cout << x1 << ' ' << labs(y2) - 1 << endl;
	if (y1 != y2 && x1 == x2) cout << labs(x1) - 1 << ' ' << y2 << endl;
	return 0;
}